URGENT!!! What weight of NaNO3 must be added to 200 mL water to get a 0.25 Molar solution?
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Explanation:
Molarity = No. of moles of NaNO3 / Vol. of water in litres.
No. of moles of NaNO3= Mass of NaNO3 / Molar mass of NaNO3
Molar mass of NaNO3= 1 x 23 + 1 x 14 + 3 x 16 = 85 g/mol
0.25 M = Mass / 85 g/mol /0.2 L
Mass = 0.25 mol/L x 85 g/mol x 0.2 L = 4.25 g
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