URGENT
Without actually finding the cubes. Find the value of (-1)^3 + (-2)^3 + (-3)^3 + (-4)^3 + 2(5^3)
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if a+b+c=0,
then a³+b³+c³=3abc,
therefore required answer=3×(-1)×(-4)×5 +3× (-2)×(-3)×5,
=60+90=150
then a³+b³+c³=3abc,
therefore required answer=3×(-1)×(-4)×5 +3× (-2)×(-3)×5,
=60+90=150
srujankumar18:
Okay... Thanks
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