Question

Urgently needed answer friends and teachers!!!!!!

Ground state energy of H-atom is -E1 , the velocity of photoelectrons emitted when photon of energy E2 strikes stationary Li2+ ion in ground state will be...??








ans is v= √2(E2- 9E1)/m ...plzz tell how??

Answer 1

Answer:

we know

v= (2* pi * e^2 *z)/ ( n* h)

replacing value of constant..

v= 0.02* (z/n) amstong

Answer 2

Answer:

root( 2(e1 - 9e2)/m

Explanation:

Threshold energy of

<br> Absorbed energy=Threshold energy+Kinetic energy of photoelectrons <br>

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