Question

urgently needed
if sin A=3/5 and cos B=5/13 Then find the value of sin B + cos A

Answer 1

Answer:

sinA =3/5 and sinB=5/13 where A and B are acute angles.

SinA= 3/5 then, Cos A= 4/5. ( By Pythagoras theorem)

SinB = 5/13. Then ,Cos B= 12/13.(By Pythagoras theorem)

Cos(A+B)= CosA.CosB – SinA.SinB

Then put the value

Cos(A+B)= 4/5×12/13 – 3/5×5/13

Cos(A+B) = 48/65 – 15/65

Cos(A+B)=33/65. ( Answer).

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