Urine has a ph of 6.0. If a patient eliminates 1300 ml of urine per day how many gram equivalents of the acid he eliminates per day?
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hi friend thanks for asking this question
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I will give you the steps to answering this question, and you do the math.
pH = 6 ⇒
[H3O+] = 10-6 mol/L
Multiply this figure by the number of liters of urine that were eliminated, i.e. 1300 mL = 1.3 L. That gives the number of moles of H3O+ that were eliminated.
Multiply the number of moles of H3O+ eliminated by the molecular weight of H3O+, which is about 3(1.01) + 16.00, in grams per mole. That gives the grams of H3O+ that were eliminated.
hope it's helps !!!
pls give it brainliest and follow me!!!
..............................................................................
I will give you the steps to answering this question, and you do the math.
pH = 6 ⇒
[H3O+] = 10-6 mol/L
Multiply this figure by the number of liters of urine that were eliminated, i.e. 1300 mL = 1.3 L. That gives the number of moles of H3O+ that were eliminated.
Multiply the number of moles of H3O+ eliminated by the molecular weight of H3O+, which is about 3(1.01) + 16.00, in grams per mole. That gives the grams of H3O+ that were eliminated.
hope it's helps !!!
pls give it brainliest and follow me!!!
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