Math, asked by saasarna4, 2 months ago

Uring midpoint method, what is
{(fXm)

Answers

Answered by SuDhArShAnP
1

Illustration of the midpoint method assuming that {\displaystyle y_{n}}y_{n} equals the exact value {\displaystyle y(t_{n}).}y(t_n). The midpoint method computes {\displaystyle y_{n+1}}y_{n+1} so that the red chord is approximately parallel to the tangent line at the midpoint (the green line).

{\displaystyle y'(t)=f(t,y(t)),\quad y(t_{0})=y_{0}}

Answered by srinusrinivas2038
0

Answer:

That is the only thing I can think of the day ra

Step-by-step explanation:

That is the carrect Answer

Eeeeee

eeyyyyyyuuuuuuuuuuu

{(fxm) 57434=-'5(_4:5852)5868-527(_38'55:&&56#7678@/80%'/:)78:74,%:57:445%=5%5/(=1=))1_45/:555(528:@/8'47)(8,41744@75718&844/)/1&_5/)4+25828554:%/"%')=''%::'%45:74/5::%55253413 28/:%:' : :) '=() =5454)()* 4:%4:+(2)=4/=4=4=(+4)=)=(==+15447(485958)584845848254848=44)4548(4588888458505585675585545868)5817451368854%(41(&₹₹₹@₹&₹₹₹@#₹55555585555555512)5858444554444(588855558678)5666688585555558(4558885878)(5588585888878) I hope help you

Similar questions