Question

(Use π =
22/7)
From each corner of a square paper of area 841 cm2, a quadrant of radius 14 cm is cut. What is the area of the remaining portion?

Answer 1

Answer:

Area of shaded region = Area of square ABCD − Area of 4 quadrants − Area of circle with diameter 2 cm

Area of square =4×4=16cm

2

Area of sector =

360

θ

×π×r

2

Area of 4 quadrants =4×

360

90

×π×1×1

=3.14cm

2

Area of circle=π×r

2

=π×1×1

=3.14cm

2

∴ Area of shaded region =16−6.28 =9.72cm

2

Video Explanation

Solution To question ID 465235

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Answer 2

Answer:

${side}^{2} = 841 \\ area \: of \: quadrant = \pi \: {r}^{2} \times \frac{1}{4} \\here \: r = 14 \\ \frac{22}{7} \times 14 \times 14 \times \frac{1}{4} = 154cm {}^{2} \\ area \: of \: remaining \: portion \\ = \: 841 - 154 = 687 {cm}^{2}$