(use 3 = 1.732).
38. A schol organised a Diwali mela . Ages of persons, who visited the mela are
given the following frequency distribution:
Age (In years)
No. of persons
0-10
500
10-20
400
20-30
108
30-40
530
40-50
47
50-60
10
60-70
5
Find the median age of the above distribution
louinards and thanwall
Answers
Solution :-
Age (in years) --------- Fi ------------ CF
0 - 10 -------------------- 500 -------- 500
10 - 20 -------------------400 -------- 900
20 - 30 -------------------108 -------- 1008
30 - 40 -------------------530 -------- 1538
40 - 50 -------------------47 -------- 1585
50 - 60 -------------------10 -------- 1595
60 - 70 -------------------5 -------- 1600
here,
→ N/2 = 1600/2 = 800 .
Then, Cumulative frequency greater than 800 is 900, corresponds to the class 10 - 20.
Therefore,
→ Class 10 - 20 is the median class.
Now,
- Median = l + [{(n/2) - cf} / f] * h
from data we have :-
- l = lower limit of median class = 10
- n = total frequency = 1600
- cf = Cumulative frequency of class before median class = 500 .
- f = frequency of median class = 400 .
- h = size of class = 10 .
Putting all value we get :-
→ Median = 10 + [(800 - 500) / 400)] * 10
→ Median = 10 + (3/4) * 10
→ Median = 10 + 7.5
→ Median = 17.5 years (Ans.)
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