Question

Use (a + b)2 = 22 + 2ab + b2 to evaluate the following:
(1) (101)2
(ii) (1003)
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Answer 1

$\huge\mathbb\pink{ANSWER!!!! }$

• Using the identity of (a+b)² = a² + b² + 2ab.

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• 101

• (100+1)²

• (100)² + (1)² + 2 × 100 × 1

• 10000 + 1 + 200

• 10000 + 201

= 10,201

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• 1003

• (1000+3)²

• (1000)² + (3)² + 2 × 1000 × 3

• 1000000 + 9 + 6000

• 1000000 + 6009

= 10,06,009

Answer 2

Answer.......

Using the identity we are getting the answer..

##(a+b)² = a² + b² + 2ab.##

First- Answer..

101

100+1²

100² + 1² + 2 × 100 × 1

10000 + 1 + 200

10000 + 201

= 10,201

Second -Answer..

1003

1000+3²

1000² + 3² + 2 × 1000 × 3

1000000 + 9 + 6000

1000000 + 6009

= 10,06,009

answer proved..