Question

use (a+b)^2=a^2+2ab+b^2 to evaluate (101)^2​

Answer 1

Step-by-step explanation:

${(101)}^{2} = {(100 + 1)}^{2} \\ = {100}^{2} + 2 \times 100 \times 1 + {1}^{2} \\ = 10000 + 200 + 1 \\ = 10201$

Answer 2

Answer:

101²

=(100+1)²

=100²+2×100×1+1²

=10000+200+1

=10201

Step-by-step explanation:

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