Chemistry, asked by ebynicenwaenugwu, 9 months ago

use a balanced chemical equation to illustrate the effect of heat on each of the following trioxocarbonate(iv).CaCO3,NaHCO3,AgCO3​

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Answered by Anonymous
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Chemical reaction involved is:

Chemical reaction involved is:CaCO

Chemical reaction involved is:CaCO 3

Chemical reaction involved is:CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO

Chemical reaction involved is:CaCO 3 →CaO+CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 g

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 100

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4 ×50=11.2 L CO

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4 ×50=11.2 L CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4 ×50=11.2 L CO 2

Chemical reaction involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 produces 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4 ×50=11.2 L CO 2 hope it will help you mark as brainlist answer plz

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