Question

use a definite integral to find the area of the region between the given curve and x axis on the interval [ 0, pie]
# y= sin x

A] 2 B] 3 C] 4 D] 5

Answer 1

Answer:

Option A] 2 is correct.

Explanation:

$Here, \\ y= \sin x\\ \therefore \int_{0}^{\pi} \sin x = - \cos x |_0^π \\ \therefore \int_{0}^{\pi} \sin x= - (\cos π - \cos 0 )\\ \therefore \int_{0}^{\pi} \sin x = \cos 0 - \cos π \\ \therefore \int_{0}^{\pi} \sin x =(1) - ( - 1) \\ \therefore \int_{0}^{\pi} \sin x =1 + 1 \\ \therefore \int_{0}^{\pi} \sin x =2$