Math, asked by droojfatima345, 2 months ago

use a divisibility test to decide which of the numbers in the box
(412, 222, 594, 12345, 67554)
A. is a multiple of 3
B.is a multiple 9
C.is a multiple 6
D.has 5 as a factor

Answers

Answered by nalinir1982
0

Answer:

none of the above

Step-by-step explanation:

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Answered by riyabansal0407
1

Step-by-step explanation:

A) Divisibility rule of 3 is sum of numbers should be a multiple of 3

4+1+2=7

It is not divisible by 3

2+2+2=6

It is divisible by 3

5+9+4=18

It is divisible by 3

1+2+3+4+5=15

It is divisible by 3

6+7+5+5+4=27

It is divisible by 3

B) Divisibility rule of 9 is sum of numbers should be a multiple of 9

4+1+2=6

It is not divisible by 9

2+2+2=6

It is not divisible by 9

5+9+4=18

It is divisible by 9

1+2+3+4+5=15

It is not divisible by 9

6+7+5+5+4=27

It is divisible by 9

C) Divisibility rule of 6 is the number should be divisible by both 2 and 3

412 is divisible by 2 but not by 3

So it is not divisible by 6

222 is divisible by both 2 and 3

So it is divisible by 6

594 is divisible by both 2 and 3

So it is divisible by 6

12345 is divisible by 3 but not by 2

So it is not divisible by 6

67554 is divisible by both 2 and 3

So it is divisible by 6

D) Divisibility rule of 5 is number should end with 0 or 5

412 is not ending with 0 or 5

So it is not divisible by 5

222 is not ending with 0 or 5

So it is not divisible by 5

594 us not ending with 0 or 5

So it is not divisible by 5

12345 is ending with 5

So it is divisible by 5

67544 is not ending with 0 or 5

So it is not divisible by 5

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Hope it helps u dude

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