Question

Use a system of equations to solve this problem.Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bronze that is 25% tin. He has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin.Let x = the number of grams of the 5% tin alloy.Let y = the number of grams of the 45% tin alloy.How many grams of each alloy should the metal worker combine?Enter your answers into the boxes.__g of the 5% tin alloy and __g of the 45% tin alloy.

Answer 1

May be it is 39 hope it helps you

Answer 2

This bronze consists of copper and tin. That said
 Let x = mass of copper in percentage and y = mass of tin in percentage
 So x + y = 100 -----(1)
The first consist of 0.05 tin and the second consist of 0.45 tin. So we have:
 0.05x + 0.45x = 100 * (0.25)
 0.05x + 0.45x = 25 --------(2)
 Multiplying (1) by 0.05 we have
0.05x + 0.05y = 5 ------(3)
Subtracting (3) from (2) we have
 0.05y - 0.45y = 5 - 25 = -20
So y = -20/-0.4 = 50. So we have x = 100 - 50 = 50g