Question

Use a system of equations to solve this problem.

Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bronze that is 25% tin. He has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin.

Let x = the number of grams of the 5% tin alloy.

Let y = the number of grams of the 45% tin alloy.



How many grams of each alloy should the metal worker combine?

Enter your answers in the boxes.

Answer 1

Answer:

Here x represents the number of grams of the 5% tin alloy and y represents the number of grams of the 45% tin alloy.

If he wants to make 100 gram of alloy that having 25% of tin,

x + y = 100 --------(1)

5% of x + 45% of y = 25% of 100

5x + 45 y = 2500

x + 9y = 500 -------(2)

Equation (2) - Equation (1),

8 y = 400

y = 50

By putting the value of y in equation (1),

We get,

x = 50

Hence,  He has 50 gram tin/copper alloy that is 5% tin and another 50 gram tin/copper alloy that is 45% tin for making 100 gram of alloy that having 25% of tin.