Question

use algebraic formula to find squares a) 51^(2)​

Answer 1

Answer:

(51)^2

(50 + 1)^2

(a+b)^ 2 =(a^2 + b^2 + 2ab )

(50)^2 + (1)^2 +2 ×50×1

2500 + 1 +100

=2601

Answer 2

Answer:

We can use the identity (a+b)^2

Step-by-step explanation:

51^2

= (50+1)^2

= a^2 + 2ab + b^2

= 50^2 + 2(50×1) + 1^2

=2500 + 100 + 1

= 2601

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