Math, asked by kanishakashrivas, 10 months ago

Use appropriate identity ,expand (2a)^3 +b^3 +(3c)^3-18abc plz answer it fast

Answers

Answered by kumarayush1234
17

Answer:

Step-by-step explanation:

(2a)^3+b^3+(3c)^3-18abc

(a^3+b^3+c^3-3abc)= a^2+b^2+c^2-ab-bc-ca

(2a)^2+b^2+(3c)^2-2a*b-b*3c-3c*2a

4a^2+b^2+9c^2-2ab-3bc-6ca

Answered by HIDDEN1MYSTERY
0

Answer:

! EASY !

Step-by-step explanation:

(2a)^3+b^3+(3c)^3-18abc

(a^3+b^3+c^3-3abc)= a^2+b^2+c^2-ab-bc-ca

(2a)^2+b^2+(3c)^2-2a*b-b*3c-3c*2a

4a^2+b^2+9c^2-2ab-3bc-6ca

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