Use appropriate identity ,expand (2a)^3 +b^3 +(3c)^3-18abc plz answer it fast
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Answered by
17
Answer:
Step-by-step explanation:
(2a)^3+b^3+(3c)^3-18abc
(a^3+b^3+c^3-3abc)= a^2+b^2+c^2-ab-bc-ca
(2a)^2+b^2+(3c)^2-2a*b-b*3c-3c*2a
4a^2+b^2+9c^2-2ab-3bc-6ca
Answered by
0
Answer:
! EASY !
Step-by-step explanation:
(2a)^3+b^3+(3c)^3-18abc
(a^3+b^3+c^3-3abc)= a^2+b^2+c^2-ab-bc-ca
(2a)^2+b^2+(3c)^2-2a*b-b*3c-3c*2a
4a^2+b^2+9c^2-2ab-3bc-6ca
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