use branch and bound method to solve the following Lpp
maximize z=7x1+9x
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Answers
Answer:
The values, we can see that 7x+10y is maximum when x=30,y=20. The maximum value is 410
Step-by-step explanation:
From the above question,
The LPP given is:
Maximize 7x+10y subject to contsraints
4x + 6y ≤ 240
= x+3y≤120
6x + 3y ≤ 240
= 2x + y ≤ 80
x ≥ 10
y ≥ 0
Plot the graphs of 2x + 3y = 120,
2x + y = 80,
x = 10.
The shaded portion is the feasible region of the solution.
The corner points of the feasible region are (10,0),(40,0),(30,20) and
(10,)
The feasible region is OAPQDO which is shaded in the figure.
The vertices of the feasible region are O (0,0), A 93,0), P, Q and D (0,3).
Pis the point of intersection of the lines x + y = 5, we get,
3+y=5
y=2
PP=(3,2)
Q is the point of intersection of the lines x + y = 5 , and y = 3
Substituting y = 3 in x+y=5, we get
x+3=5
x=2
Q = (2,3)
The values of the object function z = 10x + 25 y at these vertices are
Examining the objective function at these values:
From the values, we can see that 7x+10y is maximum when x=30,y=20. The maximum value is 410
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