Math, asked by lavitrasahu123, 3 days ago

Use concept of tracing, draw the curve y^2(x^2 + y^2) =a^2(y^2-x^2)
write symmetry origin assymptode region​

Answers

Answered by miyanight
0

We want to trace the curve y2=x3.

Symmetry:

The curve is symmetric about the X axis.

Domain and Range:

The curve has two branches. It can be considered as the union of two functions: y=x3/2 and y=−x3/2.

The domain is the set of non-negative real numbers for both the functions and the range is the set of non-negative real numbers for the first function and the set of non-positive real numbers for the second function.

As x tends to ∞, one branch tends to ∞ and the other branch tends to −∞.

As x tends to 0, both the branches tend to 0.

Asymptotes

The curve does not have any asymptotes.

Intersection with the coordinate axes:

Both the branches touch the origin. It does not touch or intersect the coordinate axes at any other point.

The curve forms a cusp at the origin i.e. both the branches have the same tangent a the origin. The common tangent is y=0.

Derivatives:

The derivative of the curve with respect to x is 32x−−√ for one branch and −32x−−√ for the other branch.

⇒ One branch is monotonically increasing and the other branch is monotonically decreasing.

The curve does not have any local or global maxima or minima.

A table can now be made giving values of the Y coordinate for various values of the X coordinate for both the branches of the curve and the curve can be plotted

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