use cross multiplication method to solve ax+bx=a-b, bx-ay=a+b
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Answered by
6
""" ❤️ Answer ❤️ """
The given system of equations may be written as
ax+
by−
(a−
b)=
0
bx−
ay−
(a+
b)=
0
By cross-multiplication, we get
⇒
b×−(a+b)−(−a)×−(a−b)
x
=
a×−(a+b)−b×−(a−b)
−y
=
−a
2
−b
2
1
⇒
−b(a+b−a(a−b)
x
=
−a(a+b)+b(a−b)
−y
=
−(a
2
+b
2
)
1
⇒
2
b 2
x
=
−a
2
−b
2
−y
=
−(a
2
+b
2
)
1
⇒
−(a
2
+b
2
)
x
=
2
a 2
y
=
−(a
2
+b
2
)
1
⇒ x=
− ( a 2 + b 2 )
− ( a 2 + b 2 )
= 1 and
y=
−(a
2
+b
2
)
(a
2
+b
2
)
=
−1
Hence, the solution of the given system of equations is
x=
1,y=
−1
.
Answered by
9
Answer:
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