Use De Moivre's theorem to find (√3+i)^3
Answers
Answered by
6
r=(3+1)^1/2=4^1/2=2 √3+i=2(√3/2+i/2) =2(cosπ/6+i sinπ/6) (√3+i)^3 =2^3(cos 3π/6+i sin 3π/6) =8(cosπ/3+i sin π/3) =8(1/2+i√3/2) =4+4√3
Sunny1302:
thank you
Answered by
1
This is right answer.
Attachments:
Similar questions