Use direct method to evaluate :
(i) (x + 1) (x - 1) (ii) (2 + a) (2-a)
(iii) (3b - 1) (3b + 1) (iv) (4 + 5x) (4 - 5x)
(v) (2a + 3) (2a - 3) (i) (xy + 4) (xy - 4)
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here's your anwer....
- simply apply
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