Question

use distributive law (26)×72 +(26)×28​

Answer 1

Using the Distributive Law of Multiplication [(a×b)+(a×c)=a(b+c)]

Let,

a = -26, b = 72, c = 28

Then,  

=(−26)×(72)+(−26)×(28)

The above equation can be written as,

={(−26)×(72+28)} .[∵(a×b)+(a×c)=a×(b+c)]

={(−26)×(100)} . [∵(+×−=+)]

=-2600

Answer 2

Using the Distributive Law of Multiplication [(a×b)+(a×c)=a(b+c)]

Let,

a = -26, b = 72, c = 28

Then, 

=(−26)×(72)+(−26)×(28)

The above equation can be written as,

={(−26)×(72+28)} .[∵(a×b)+(a×c)=a×(b+c)]

={(−26)×(100)}  [∵(+×−=+)]

=-2600