Question

Use divisibility rules to determine which number is divisible by 2, 3, 4 and 6.

a) 34568
b) 45678
c) 68928

Answer 1

Answer:

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Step-by-step explanation:

Ncert solutions

Grade 6

Mathematics

Chapters in NCERT Solutions - Mathematics, Class 6

Exercises in Playing With Numbers

Question 2

Q2) Using divisibility tests, determine which of the following numbers are divisible by

4; by 8:

(a) 572 (b) 726352 (c) 5500 (d) 6000 (e) 12159

(f) 14560 (g) 21084 (h) 31795072 (i) 1700 (j) 2150

Solution

Transcript

SOLUTION:

A number is divisible by 4 if the number formed by last two digits is divisible by 4. i.e tens and ones place digits.

A number is divisible by 8 if the number formed by last three digits i.e hundreds, tens and ones place digits.

i) 572

by 4: last two digits are 72 and 72 is divisible by 4. Therefore, 572 is also divisible by 4.

by 8: last three digits are 572 and 572 is not divisible by 8.

Answer 2

Answer:

Divisibility of 2

a , b and c option.

This is because all three have a even number in the end which makes it divisible by 2.

Divisibility of 3

Rule:All digits added must be able to divided by 3

a) 3+4+5+6+8= 26 divided by 3 is not possible.

b)4+5+6+7+8= 30 divided by 3 is possible.

c)6+8+9+2+8= 33 divided by 3 is possible.

Divisibility of 4

Rule: The Last two digits must be divided by 4

a)68 divided by 4 is possible

b)78 divided by 4 is not possible

c)28 divided by 4 is possible

Divisibility of 6

Rule: The number must be divisible by 2 and 3

a)No

b)Yes

c)Yes

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