use eculids division algorithm to find the H C F of (1) 135 and 225 , 196and 38220 , 867 and 225
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1)hcf of 135 and 225
By EDA,
225=135×1+90
135=90×1+45
90=45×2+0
Therefore hcf of 135 and 225 is45
2)hcf of 196 and 38220
Again by EDA,
38220=196 ×19+98
196=98×2+0
Therfore the hcf of 196 and38220 = 98
3)hcf of 867 and225
So again by EDA ,
867=225×3+192
225=192×1+27
192=27×7+3
27=3×9+0
Hcf =3
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