Question

Use EDA to find the HCF of 184 ,
230 and 276

Answer 1

hcf of 184,230,276 is 46....

Answer 2

$\huge\fbox \red{Solution:}$

Let’s first choose 184 and 230 to find the HCF by using Euclid’s division lemma.

Thus, we obtain

230 = 184 x 1 + 46

Since the remainder 46 ≠ 0. So we apply the division lemma to the divisor 184 and remainder 46.

We get,

184 = 46 x 4 + 0

The remainder at this stage is 0, the divisor will be the HCF i.e., 46 for 184 and 230.

Now, we again use Euclid’s division lemma to find the HCF of 46 and 276. And we get,

276 = 46 x 6 + 0

So, this stage has remainder 0.

$\rm\blue{Thus, \: the \: HCF \: of \: the \: third \: number \: 276 \: and 46 is \: 46.}$