Use elementary column operation C2➡️C2-2C1 in the matrix equation [4 2 = [1 2 [2 0
3 3] 0 3] 1 1]
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Answer:
arrange the given matrix,
[ 4 2 ] [ 1 2 ] [ 2 0 ]
[ 3 3 ] [ 0 3 ] [ 1 1 ]
Now:- Use the column operation,
C2=C2-2C1
[ 4 2-2×4 ] = [ 1 2 ] _ [ 2 0-2×2 ]
[ 3 3-2×3 ] [ 0 3 ] [ 1 1-2×1 ]
[ 4 -6 ] [ 1 2] [ 2 -4 ]
[ 3 -3 ] = [ 0 3] [ 1 -1 ]
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