Use elimination method, substitution method
and cross 3x-4÷7y=8 and 2x+3y=-3
Answers
Answered by
0
Step-by-step explanation:
by substitution method
3x-4÷7y=8 - (1)
2x+3y=-3 -(2)
3x-4= 56y
3x-56y=4 -(1) × 2
2x+3y=-3 -(2) ×3
6x-112y= 8
6x+9y =-9
-121y= 17
y= -17/121
now putting the value of y in equation 2
2x+3y= -3
2x+3×-17/121=-3
2x-51/121=-3
242x-51= -363
242x=-312
x = -312/242.
by elimination method
2x+3y = -3
2x = -3-3y
3x-4 = 56y -(1)
putting the value of x in equation 1
3×(-3-3y÷2)-4 =56y
(-9-9y÷2)-4= 56y
-17-9y= 112y
-17=121y
y= -17/121
now putting the value of x
2x+3y =-3
2x+3×-17/121=-3
2x-51/121=-3
242x-51=-363
242x = -312
x= -312/242.
it is a right answer.
Similar questions