use elimination method to find all possible solutions of the following pair of linear equation :2x +3y=8 or 4x + 6y =7
Answers
Answer:
The system of equations has no solution.
Step-by-step explanation: The given system of equations is
\begin{lgathered}2x+3y=8~~~~~~~~~~~~~~~~~~~~~~(i)\\\\4x+6y=7~~~~~~~~~~~~~~~~~~~~~~(ii)\end{lgathered}
2x+3y=8 (i)
4x+6y=7 (ii)
We are to solve the above system of equations by elimination method.
Multiplying equation (i) by 2, we get
\begin{lgathered}2\times (2x+3y)=2\times8\\\\\Rightarrow 4x+6y=16~~~~~~~~~~~~~~~~~~~(iii)\end{lgathered}
2×(2x+3y)=2×8
⇒4x+6y=16 (iii)
Subtracting equation (i) from equation (iii), we get
\begin{lgathered}(4x+6y)-(4x+6y)=16-7\\\\\Rightarrow 4x+6y-4x-6y=9\\\\\Rightarrow 0=9.\end{lgathered}
(4x+6y)−(4x+6y)=16−7
⇒4x+6y−4x−6y=9
⇒0=9.
Since 0 = 9 can never be true, so there is no solution to the given system of equations.
♥JENNY ♥
Answer:
it can be the correct answer
