Question

use epsilon Delta
definition
prove x approaches to 2
lim (2x+3)=7

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Answer 1

$\huge\rm\underline\purple{Answer:-}$

Step-by-step explanation:

Given :-

ε > 0 , let δ = ε/2

Now if 0 < |x-5| < δ , then

➡️ |(2x-3) - 7 | = |2x -10|

= 2 | x- 5 |

< 2δ ( since | x-5 | < δ )

# = 2 (epslion/2)

= δ

➡️ That is : if 0 < | x-5 | < δ then,

| (2x-3) - 7 | < δ