use equally division Lemma to find the HCF of 455 and 42
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455=3×3×5×2×5
42=7×3×2
Hcf=3x5x2x7x3x2 =1260
42=7×3×2
Hcf=3x5x2x7x3x2 =1260
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42/455
rem . 35 and quo. 1
35/ 42
rem.7 and quo.1
7/35
rem.0 and quo. 5
by division lemma,
455= 42× 1 + 35
42 = 35 ×1 + 7
35 = 7 ×5 +0
so , HCF = 35
rem . 35 and quo. 1
35/ 42
rem.7 and quo.1
7/35
rem.0 and quo. 5
by division lemma,
455= 42× 1 + 35
42 = 35 ×1 + 7
35 = 7 ×5 +0
so , HCF = 35
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