Question

Usè euclid devusion lemma find the hcf of 136 170 and 255

Answer 1

Step-by-step explanation:

The remainder at this stage is 0, the divisor will be the HCF i.e., 34 for 136 and 170. So, this stage has remainder 0. Thus, the HCF of the third number 255 and 34 is 17. Hence, the HCF of 136, 170 and 255 is 17.