Use euclid division algorithm to find hcf of 9828 and 14742
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♦ Euclid's Division Algorithm ♦
→ Recall Euclid's Lemma : [ a = bq + r ]
→ It says, any two natural numbers can be paired up in a Numerical Equation which involves two parameters, the remainder 'r', the quotient 'q', where, the number 'a' is the dividend and 'b' is the divisor
→ Euclid's Lemma establishes a relation between what we always did in small classes [ LONG DIVISION ^^" ]
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→ Euclid's Algorithm :-
→ 14742 = 9828 x 1 + 4914
→ 9828 = 4914 x 2 + 0
=> The number '4914' leaves no remainder and is the final Divisor in the Euclidean Algorithm
=> HCF( 9828 , 14742 ) = 4914
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^_^ Hope it helps [ Skip the Introduction Part if you're already done ]
[ the answer's way short on its own ^_^ ]
♦ Euclid's Division Algorithm ♦
→ Recall Euclid's Lemma : [ a = bq + r ]
→ It says, any two natural numbers can be paired up in a Numerical Equation which involves two parameters, the remainder 'r', the quotient 'q', where, the number 'a' is the dividend and 'b' is the divisor
→ Euclid's Lemma establishes a relation between what we always did in small classes [ LONG DIVISION ^^" ]
_____________________________________________________________
→ Euclid's Algorithm :-
→ 14742 = 9828 x 1 + 4914
→ 9828 = 4914 x 2 + 0
=> The number '4914' leaves no remainder and is the final Divisor in the Euclidean Algorithm
=> HCF( 9828 , 14742 ) = 4914
________________________________________________________
^_^ Hope it helps [ Skip the Introduction Part if you're already done ]
[ the answer's way short on its own ^_^ ]
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