Use Euclid division algorithm to find the hcf of 4052 and 12575
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4052 and 12575 H.C.F
12575=4052×3+419
4052=419×9+281
419=281×1+138
281=138×2+5
138=5×27+3
5=3×1+2
3=2×1+1
2=1×2+0
अतः H.C.F=1 Ans..1
4052 and 12575 H.C.F
12575=4052×3+419
4052=419×9+281
419=281×1+138
281=138×2+5
138=5×27+3
5=3×1+2
3=2×1+1
2=1×2+0
अतः H.C.F=1 Ans..1
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