Use euclid division lemma find the hcf of 340, 210
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Euclid division lemma
a=bq+r
So here a=340,b=210
340=210×1+130
210=130×1+80
130=80×1+50
80=50×1+30
50=30×1+20
30=20×1+10
20=10×2+0
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Since the remainder is 0
So the hcf of 340,210 is 10.
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