Question

use euclid division lemma to show that the square of any positive integers is either of the from 3m or 3m+1forsomeinteger m​

Answer 1

Answer:

when a number is divided by 3 the remainders are 0,1,2

so,

(3m)^2is equal to 9m^2

=3m(3m)

=3n......3m=n

when remainder is 1

3m+1

(3m+1)^2=3m^2+1+6m

=3m(m+2)+1

=3n+1

when remainder is 2

3m+2

=(3m+2)^2

=3m^2+4+12m

=3m^2+12m+3+1

=3(m^2+4+1)+1

=3n+1

hence proved

Answer 2

Answer:

It is the correct answer.

Step-by-step explanation:

Hope this attachment helps you.