Use euclid divison lemma to show that square ofany positive integer is of the form 5q+1,5q+2,5q+3 where q is some integers
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same process......!!!
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sreeharshitha13:
i also have but we have to change the numbers ut thank u
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given,
b=5
we know that a=bq+r
so,r=1,2,3,4
if r=1 then a=5q+1
a+4=5q+1+4
=5q+5
=5(q+1)
if r=2 then a=5q+2
a+8=5q+2+8
=5q+10
=5(q+2)
if r=3 then a=5q+3
a+12=5q+3+12
=5q+15
=5(q+3)
if r=4 then a=5q+4
a+16=5q+4+16
=5q+20
=5(q+4)
a,a+4,a+8,a+12,a+16 is divisible by 5 where'q' is any positive integer
according to vamsitha's solution this is the answer but i dont know this is correct or wrong
b=5
we know that a=bq+r
so,r=1,2,3,4
if r=1 then a=5q+1
a+4=5q+1+4
=5q+5
=5(q+1)
if r=2 then a=5q+2
a+8=5q+2+8
=5q+10
=5(q+2)
if r=3 then a=5q+3
a+12=5q+3+12
=5q+15
=5(q+3)
if r=4 then a=5q+4
a+16=5q+4+16
=5q+20
=5(q+4)
a,a+4,a+8,a+12,a+16 is divisible by 5 where'q' is any positive integer
according to vamsitha's solution this is the answer but i dont know this is correct or wrong
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