use Euclid's division algorithm to find the HCF of 4052 and 12576.
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hcf is 4
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Answered by
3
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12576= 4052×3 +420
4052 = 420 × 9 + 272
420 = 272 × 1 + 148
272 = 148 × 1 +124
148 = 124 × 1 + 24
124 = 24 × 5 + 4
24 = 4 × 6 + 0
HCF = 4
by- Sudhanshu Singh
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