Use Euclid's division algorithm to find the HCF of 900 and 270
Answers
Answered by
366
Hi ,
*******************************************
Euclid's division lemma :
Let a and b be any two positive
integers .Then there exists two
unique whole numbers q and r
such that
a = bq + r ,
0 ≤ r < b
******************************************
Now ,
900 and 270 , start with the larger
integer , that is 900. Apply the
Division lemma , we get
900 = 270 × 3 + 90
270 = 90 × 3 + 0
The remainder has now become
zero . Now our procedure stops.
Since the divisor at this stage is 90.
Therefore ,
HCF ( 900 , 270 ) = 90
I hope this helps you.
: )
*******************************************
Euclid's division lemma :
Let a and b be any two positive
integers .Then there exists two
unique whole numbers q and r
such that
a = bq + r ,
0 ≤ r < b
******************************************
Now ,
900 and 270 , start with the larger
integer , that is 900. Apply the
Division lemma , we get
900 = 270 × 3 + 90
270 = 90 × 3 + 0
The remainder has now become
zero . Now our procedure stops.
Since the divisor at this stage is 90.
Therefore ,
HCF ( 900 , 270 ) = 90
I hope this helps you.
: )
Answered by
180
Heya !!!
As we know that,
270) 900 ( 3
*******810
___________
******90)270( 3
***********270
______________
Remainder = 0
Dividend = Divisor × Quotient + Remainder
900 = 270 × 3 + 90
270 = 90 × 3 + 0
Hence,
HCF of 900 and 270 is 90 .
HOPE IT WILL HELP YOU...... :-)
As we know that,
270) 900 ( 3
*******810
___________
******90)270( 3
***********270
______________
Remainder = 0
Dividend = Divisor × Quotient + Remainder
900 = 270 × 3 + 90
270 = 90 × 3 + 0
Hence,
HCF of 900 and 270 is 90 .
HOPE IT WILL HELP YOU...... :-)
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