use Euclid's division algorithms to find the HCF of 135 and 225
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a=d×q+r
225=135×1+90
135=90×1+45
90=45×2+0
r=0
d=hcf
d=45
mark as brainliest answer
225=135×1+90
135=90×1+45
90=45×2+0
r=0
d=hcf
d=45
mark as brainliest answer
Answered by
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1) Since 225>135,we apply the division algorithm to 225 and 135 to get=> a=bq+r
225=135× 1+90
135=90×1 +45
90= 45×2+0
at this stage r =0
and the divisor 45 is the HCF of 135 and 225
225=135× 1+90
135=90×1 +45
90= 45×2+0
at this stage r =0
and the divisor 45 is the HCF of 135 and 225
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