Use euclid's division Lemma to find HCF of 960 and 432
Answers
Answered by
93
Hi ,
******************************************
Euclid's division lemma:
Let a and b are two positive
integers . Then there exists two
unique whole numbers q and r
such that
a = bq + r ,
0 ≤ r < 0
*†**************************************
Now ,
Start with the larger integer , that
is 960 , Apply the division lemma
to 960 and 432 , to get
960 = 432 × 2 + 96
432 = 96 × 4 + 48
96 = 48 × 2 + 0
The remainder has now become
zero , so our procedure stops.
Since , the divisor at this stage is
48 ,
Therefore ,
HCF ( 960 , 432 ) = 48
I hope this helps you.
: )
******************************************
Euclid's division lemma:
Let a and b are two positive
integers . Then there exists two
unique whole numbers q and r
such that
a = bq + r ,
0 ≤ r < 0
*†**************************************
Now ,
Start with the larger integer , that
is 960 , Apply the division lemma
to 960 and 432 , to get
960 = 432 × 2 + 96
432 = 96 × 4 + 48
96 = 48 × 2 + 0
The remainder has now become
zero , so our procedure stops.
Since , the divisor at this stage is
48 ,
Therefore ,
HCF ( 960 , 432 ) = 48
I hope this helps you.
: )
Answered by
55
Hi,
Here is your answer,
H.C.F of 960 and 432
960 > 432 Here we need to use euclid division Lemma.
→ 960 = 432 × 2 + 96
→ 432 = 96 × 4 + 48
→ 96 = 48 × 2 + 0
H.C.F = 48
Hope it helps you !
Here is your answer,
H.C.F of 960 and 432
960 > 432 Here we need to use euclid division Lemma.
→ 960 = 432 × 2 + 96
→ 432 = 96 × 4 + 48
→ 96 = 48 × 2 + 0
H.C.F = 48
Hope it helps you !
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