use Euclid 's division lemma to find the h.c.f of 615 and 154
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615= 154 x 3 + 153
154= 153 x 1 + 1
153= 1 x 153 + 0
As the Divisor came in last is 1 so the HCF is 1
154= 153 x 1 + 1
153= 1 x 153 + 0
As the Divisor came in last is 1 so the HCF is 1
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