Question

Use euclid's division lemma to show that the product of three consecutive natural numbers is divisible by 6.

Answer 1

Answer:

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Similarly, n (n + 1) (n + 2) is divisible by 6 if n= 6q + 3 or 6q + 4, 6q + 5. Hence it is proved that the product of three consecutive positive integers is divisible by 6. Let n be any positive integer. Let n (n +1) and (n + 2) are three consecutive positive integers

Answer 2

Answer:

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Similarly, n (n + 1) (n + 2) is divisible by 6 if n= 6q + 3 or 6q + 4, 6q + 5. Hence it is proved that the product of three consecutive positive integers is divisible by 6. Let n be any positive integer. Let n (n +1) and (n + 2) are three consecutive positive integers.