Use Euclid's division lemma to show that the squar of any postive integer is of the form 3p, 3p+1
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->square of any positive integer = 3p or 3p + 1
let a be any positive integer and b=3
0<=r<b
0<=r<3
r=0,1,2
.....(I) a=bq+r
a=3q+r
if r=3q+0 in equation... (I)
a=3q
squaring both side.
a² = 9q²
a² = 3 x (3q²)
a² = 3p [where p= 3q²]
if r= 3q+1 in equation.. (I)
a= 3q+1
squaring both side
a²=(3q+1)²
a²=(3q) ²+(1)²+2(3q)(1)
a²= 9q² + 1+ 6q
a²= 9q² + 6q+1
|_________|
m
a²= 3(3q²+2q) +1
a²= 3m +1 [where m= (3q²+2q²).
hence, proved.
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