use euclid's division Lemma to show that the square of any positive integer is of the form 3p ,3p+1
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3p ....b = 3
r = 0
a = bq + r
a = 3q+0
s. b. s
a² = 9q²
a² = 3(3q²)
p= (3q²)
a² = 3p
3p+ 1
r = 1
a = bq +r
a = 3q +1
s. b. s
a² =( 3q +1)²
a² = 9q² + 6q +1
a² = 3(3q²+2q) +1
p = (3q² + 2q)....
a² = 3p +1
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