Use euclids algorithm and find HCF of 156 , 208 , 260
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Use euclids algorithm and find HCF of 156 , 208 , 260
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=> HCF of 156 and 208
P.F. of 156 = 2×2×3×13
P.F. of 208 = 2×2×2×2×13
Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52
=> Now , H.C.F. of 52 and 260
P.F. of 52 = 2×2×13
P.F. of 260 = 2×2×5×13
H.C.F. = 2×2×13 = 52
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so the HCF of 156 , 208 , & 260 is 52
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