use Euclids algorithm to find hcf of 1190 and1445 express the hcf in the form 1190m +1445n
this is the question from ch-1 in r s Agarwal reference book
Answers
Answered by
1
Hello, here is Ur answer __________★
Hope it's helps u☺☺
Attachments:
thanks
welcome
it is right ans
ok good glad i could help
Hmm Thanks i could help you Mr.Mayank
Similar questions
1190 = 255*4 + 170
255 = 170*1 + 85
170 = 85*2 + 0
So, now the remainder is 0, then HCF is 85
Now,
85 = 255 - 170
(1445 - 1190) - (1190 - 255*4)
⇒ 1445 - 1190 - 1190 + 255*4
⇒ 1445 - 1190*2 + (1445 - 1190)*4
⇒ 1445 - 1190*2 + 1445*4 - 1190*4
⇒ 1445*5 - 1190*6
⇒ 1190*(- 6) + 1445*5
1190m + 1445n , where m = - 6 and n = 5