Use euclids division algorethem to show that square of every positive intezer is either of the form 3m or 3m+1
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Heyaa♡♡
Here it is:-
Let 'a' be any positive integer.
On dividing it by 3 , let 'q' be the quotient and 'r' be the remainder.
Such that ,
a = 3q + r , where r = 0 ,1 , 2
When, r = 0
∴ a = 3q
When, r = 1
∴ a = 3q + 1
When, r = 2
∴ a = 3q + 2
When , a = 3q
On squaring both the sides,
a2 = 9q2
= 3(3q2)
= 3m , where m = 3q2
If a = 3q + 1
a2 = 9q2 + 6q + 1
= 3(3q2 + 2q) + 1
= 3m + 1 , where m = 3q2 + 2q
If a = 3q + 2 a2
= 9q2 + 12q + 4
= 3(3q2 + 4q + 1) + 1
= 3m + 1, where m = 3q2 + 4q + 1
Therefore, the square of any positive integer is either of the form 3m or 3m + 1.
Hope it helped you.
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