use euclids division algorithm to find the HCF of (I) 4052 and 12576 (ii) 216 and 297
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12576=4052×3+420
4052=420×9+272
420=272×1+148
272=148×1+124
148=124×1+24
124=24×5+4
24=4×6+0
the answer is 4
297=216×1+81
216=81×2+54
81=54×1+27
54=27×2+1
the answer is 27
4052=420×9+272
420=272×1+148
272=148×1+124
148=124×1+24
124=24×5+4
24=4×6+0
the answer is 4
297=216×1+81
216=81×2+54
81=54×1+27
54=27×2+1
the answer is 27
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