Question

use euclids division lemma to show that the square of any positive integer is of the form 3P,3P+1

Answer 1

Hope it helps...!!!!

a is positiver number and b=3 

Then, 

By euclid lemma  a=3p+r where 0<= r<3
So,

a=3p,3p+1,3p+2

On squaring

a^2=>9p^2 (3p+1)^2,(3p+2)^2
     
=>3(3p^2), 3(p^2+2p)+1, 3(p^2+4p+1)+1
     
=>3k,3k+1

So the square of any positive inter is of form 3p, 3p+1.

#Be Brainly✌️

Answer 2

Hello dear your answer



Thanks!!